![]() ![]() I believe I also asked my host to look into it and they made some Apache setting changes. I believe the reason it works from the command line is because Tor (the proxy) is resolving the. I'm having trouble trying to retrieve a web page from a remote secure server via a proxy. I also did an echo of $proxyipport and $proxyuserpwd and it showed me the exact ip:port and user:pass as expected. I tried using a proxy with curl to see if I was possibly being blocked by the other server. The PHP cURL documentation says this: -socks5-hostname Use the specified SOCKS5 proxy (and let the proxy resolve the host name). cURL + proxy noob here, having a hard time. However, when I replaced those variables with actual ip:port, user:pass, it worked as normal. The problem is when I used $proxyipport and $proxyuserpwd in CURLOPT_PROXY and CURLOPT_USERPWD, the curl result threw the error Received HTTP code 407 from proxy after CONNECT. ![]() Im having trouble trying to retrieve a web page from a remote secure server via a proxy. On the other hand, if I set CURLOPT_RETURNTRANSFER, then I have to cache the response somewhere (in memory or in a temp file) which is sub-optimal.The format of proxies in proxy.txt is ip:port:user:pass and all proxies are working. cURL + proxy noob here, having a hard time. Configure a PHP/cURL application alongside the Fiddler Classic proxy. I can't see how to set the HTTPHOST to the referer I'm trying to be. ![]() successfully - but the HTTPHOST has my fingerprints all over it. It shows I'm successfully passing through the proxy ID, user agent, etc. If I additionally set CURLOPT_HEADER, the backend headers are also passed through, but then the client gets two copies of the HTTP headers (one from PHP, the other from Curl.) The azenv.php generic script shows that my curl request is being sent with HTTPHOST my REAL server name. However, everytime that I try to access this file from another. If I unset CURLOPT_RETURNTRANSFER, the backend response is streamed correctly, but without headers. How can I stream the zip file back to the client, without caching it, including the Content-Type and Content-Disposition headers, which contain the file type and most importantly the file name? I can use the Curl module to do that, which gives me fine control over the backend request headers and content (for instance to post some content) but I can't figure out how to stream the response back including the relevant response headers.įor example, my PHP app needs to post some JSON to the backend, which will generate a big zip file. php-proxy, but there are few ones that shares that name // too basics But in fact, no one will let you connect your browser with it, because you need to implement the tcp wrapper for the connection. ![]() Youll have to write your proxy based on the web pages youre hitting, but itll make the job. My PHP app sometimes needs to reverse proxy some content from an upstream (legacy) HTTP backend. I would recommand using Curl (php library that you might need to activate in your php.ini) Its used to manipulate remote websites, handling cookies and every http parameters you need. ![]()
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